(2x^2+5)-(5+2x^2)=0

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Solution for (2x^2+5)-(5+2x^2)=0 equation: 


Simplifying
(2x2 + 5) + -1(5 + 2x2) = 0

Reorder the terms:
(5 + 2x2) + -1(5 + 2x2) = 0

Remove parenthesis around (5 + 2x2)
5 + 2x2 + -1(5 + 2x2) = 0
5 + 2x2 + (5 * -1 + 2x2 * -1) = 0
5 + 2x2 + (-5 + -2x2) = 0

Reorder the terms:
5 + -5 + 2x2 + -2x2 = 0

Combine like terms: 5 + -5 = 0
0 + 2x2 + -2x2 = 0
2x2 + -2x2 = 0

Combine like terms: 2x2 + -2x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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